24x^2=216

Solution for 24x^2=216 equation:

24x^2=216

We move all terms to the left:

24x^2-(216)=0

a = 24; b = 0; c = -216;
Δ = b2-4ac
Δ = 02-4·24·(-216)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*24}=\frac{-144}{48}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*24}=\frac{144}{48}
=3
$